Skip to main content

Worked Example: Industrial Motor Feeder — 75 kW DOL Motor, 150 m Run

Step-by-step motor feeder cable sizing for a 75 kW direct-on-line motor with a 150 m cable run under four international standards. Covers starting current, voltage drop at starting, derating factors, and multi-standard comparison across AS/NZS 3008, BS 7671, IEC 60364, and NEC.

AS/NZS 300822 min readUpdated March 3, 2026
Share:

Scenario

ParameterValue
Motor75 kW, three-phase, 4-pole squirrel cage induction motor
Supply voltage400 V three-phase, 50 Hz (415 V for AS/NZS)
Efficiency0.935 (IE3 premium efficiency, IEC 60034-30-1)
Power factor (running)0.86 lagging
Starting methodDirect on line (DOL)
Starting current ratioIst / IFL = 7.5 (nameplate locked-rotor current)
Starting duration12 seconds to full speed (high-inertia fan load)
Starting power factor0.25 (locked rotor)
Cable route length150 m (MCC to motor terminal box)
Installation methodMulticore cable on perforated cable tray, with 5 other circuits
Ambient temperature45°C (steel mill environment)
Cable typeXLPE insulated, copper conductor, 90°C rated
Soil / enclosureOpen tray, horizontal, no direct sun exposure

This example calculates cable size under AS/NZS 3008.1.1:2017, BS 7671:2018+A2, IEC 60364-5-52, and NEC/NFPA 70:2023. The 150 m route length makes this a borderline case where voltage drop during motor starting — not steady-state current capacity — may govern cable selection.

Step 1: Calculate Motor Full-Load Current (I_FL)

For a three-phase induction motor:

IFL = P / (√3 × V × PF × η) — (Eq. 1)

Under AS/NZS (415 V):

IFL = 75,000 / (√3 × 415 × 0.86 × 0.935)

IFL = 75,000 / (1.732 × 415 × 0.86 × 0.935)

IFL = 75,000 / 578.0

IFL = 129.8 A

Under BS 7671 / IEC / NEC (400 V):

IFL = 75,000 / (√3 × 400 × 0.86 × 0.935)

IFL = 75,000 / 557.0

IFL = 134.6 A

Note: AS/NZS uses 415 V nominal (AS 60038), while BS/IEC/NEC use 400 V. This alone creates a 3.7% difference in full-load current at the outset.

Step 2: Calculate Starting Current

For DOL starting with Ist/IFL = 7.5:

Istart = 7.5 × IFL — (Eq. 2)

StandardIFL (A)Istart (A)
AS/NZS 3008129.8973
BS 7671134.61,010
IEC 60364134.61,010
NEC134.61,010

The starting current of approximately 1,000 A persists for 12 seconds as the high-inertia fan load accelerates to full speed. During this period, the cable must deliver the starting current without excessive voltage drop at the motor terminals.

Step 3: Determine Derating Factors

Each standard has different reference conditions and derating tables.

AS/NZS 3008.1.1:2017

Ambient temperature correction (k1):

Reference ambient = 40°C. Actual = 45°C.

From AS/NZS 3008.1.1:2017, Table 22, Row 45°C, Column 90°C XLPE:

k1 = 0.95

Grouping correction (k2):

6 circuits on perforated cable tray, touching.

From AS/NZS 3008.1.1:2017, Table 24, Row: 6 multicore cables on tray:

k2 = 0.73

Combined derating:

ktotal = k1 × k2 = 0.95 × 0.73 = 0.694 — (Eq. 3a)

BS 7671:2018+A2

Ambient temperature correction (Ca):

Reference ambient = 30°C. Actual = 45°C.

From BS 7671, Table C.1, Row 45°C, Column 90°C XLPE:

Ca = 0.87

Grouping correction (Cg):

6 circuits on perforated cable tray (Reference Method E).

From BS 7671, Table C.3, Row: 6 multicore on tray, touching:

Cg = 0.73

Combined derating:

Ctotal = Ca × Cg = 0.87 × 0.73 = 0.635 — (Eq. 3b)

IEC 60364-5-52

Ambient temperature correction:

Reference ambient = 30°C (same as BS 7671).

From IEC 60364-5-52, Table B.52.14, Row 45°C, Column 90°C XLPE:

Ca = 0.87

Grouping correction:

From IEC 60364-5-52, Table B.52.17, 6 multicore on tray:

Cg = 0.73

Combined derating:

Ctotal = 0.87 × 0.73 = 0.635 — (Eq. 3c)

NEC/NFPA 70:2023

Temperature correction:

From NEC Table 310.15(B)(1), 90°C column, 45°C ambient:

Ca = 0.87

Adjustment for conduit/raceway grouping:

From NEC 310.15(C)(1), Table 310.15(C)(1), 6 current-carrying conductors. For cable tray per NEC 392.80(A)(1)(a), cables rated 2,000 V or less, 6 multiconductor cables on a single-layer tray:

Cg = 0.80 (NEC 392 is more generous for open cable tray)

Continuous load factor: NEC 430.22 requires motor branch circuit conductors to have ampacity not less than 125% of the motor full-load current:

Fcont = 1.25

Combined effective derating:

Ctotal = Ca × Cg / Fcont = 0.87 × 0.80 / 1.25 = 0.557 — (Eq. 3d)

Note: NEC applies the 125% factor differently — it increases the required ampacity rather than reducing the cable rating, but the mathematical effect is equivalent.

Step 4: Calculate Required Cable Current Rating and Select Cable

The cable must have a tabulated current-carrying capacity (before derating) that satisfies:

Iz ≥ IFL / ktotal — (Eq. 4)

For NEC, the requirement is:

Iz ≥ (1.25 × IFL) / (Ca × Cg)

StandardIFL (A)ktotalRequired Iz (A)Table Reference
AS/NZS 3008129.80.694187.0Table 13, Col 17 (tray, XLPE)
BS 7671134.60.635212.0Table 4E4A, Method E
IEC 60364134.60.635212.0Table B.52.5, Method E
NEC134.60.557241.7Table 310.16, 90°C

Cable selection from each standard’s tables:

StandardRequired Iz (A)Cable SizeTabulated Rating (A)Margin
AS/NZS 3008187.070 mm²196 A (Table 13, Col 17)+4.8%
BS 7671212.095 mm²238 A (Table 4E4A, Method E)+12.3%
IEC 60364212.095 mm²238 A (Table B.52.5)+12.3%
NEC241.74/0 AWG (107 mm²)260 A (Table 310.16)+7.6%

First surprise: Based on current capacity alone, AS/NZS selects 70 mm², BS/IEC select 95 mm², and NEC selects 4/0 AWG (107 mm²). The NEC result is 53% more copper than AS/NZS. But we have not checked voltage drop yet.

Step 5: Voltage Drop at Running Current

For a three-phase circuit, voltage drop is calculated using the impedance method:

ΔV = √3 × IFL × L × (r × cos(φ) + x × sin(φ)) / 1000 — (Eq. 5)

Where r and x are the resistance and reactance per unit length (mΩ/m), and φ is the load power factor angle (cos(φ) = 0.86, sin(φ) = 0.51).

70 mm² (AS/NZS selection):

From AS/NZS 3008.1.1:2017, Table 35, 70 mm², XLPE copper, three-phase:

r = 0.321 mΩ/m, x = 0.110 mΩ/m

ΔV = 1.732 × 129.8 × 150 × (0.321 × 0.86 + 0.110 × 0.51) / 1000

ΔV = 33,730 × 0.332 / 1000

ΔV = 11.20 V = 2.70% (of 415 V)

95 mm² (BS 7671 / IEC selection):

From BS 7671, Table 4E2B, 95 mm²:

r = 0.236 mΩ/m, x = 0.110 mΩ/m

ΔV = 1.732 × 134.6 × 150 × (0.236 × 0.86 + 0.110 × 0.51) / 1000

ΔV = 34,979 × 0.259 / 1000

ΔV = 9.06 V = 2.27% (of 400 V)

4/0 AWG / 107 mm² (NEC selection):

From NEC Chapter 9, Table 9, 4/0 AWG copper:

r = 0.203 mΩ/m, x = 0.110 mΩ/m

ΔV = 1.732 × 134.6 × 150 × (0.203 × 0.86 + 0.110 × 0.51) / 1000

ΔV = 34,979 × 0.231 / 1000

ΔV = 8.08 V = 2.02% (of 400 V)

All selections pass the running voltage drop limits (AS/NZS 3000 Cl. 3.6.2: 5%, BS 7671 Appendix 12: 5%, IEC 60364-5-52 Cl. 525: 5%, NEC 215.2 Informational Note: 5%).

Step 6: Voltage Drop at Starting Current — The Critical Check

This is where the 150 m route length becomes decisive. At starting, the power factor drops to 0.25 (cos(φ) = 0.25, sin(φ) = 0.968), and the current increases to 7.5× full load:

ΔVstart = √3 × Istart × L × (r × cos(φstart) + x × sin(φstart)) / 1000 — (Eq. 6)

70 mm² at 973 A starting current (AS/NZS):

ΔVstart = 1.732 × 973 × 150 × (0.321 × 0.25 + 0.110 × 0.968) / 1000

ΔVstart = 252,801 × 0.186 / 1000

ΔVstart = 47.0 V = 11.3% (of 415 V)

Motor terminal voltage = 415 − 47.0 = 368 V

Starting torque retention (torque is proportional to V²):

Tstart / Trated = (368 / 415)² = 0.786 = 78.6% — (Eq. 7)

This is borderline. IEEE 141 (Red Book) recommends a minimum of 80% terminal voltage (64% starting torque) for reliable starting. At 78.6% torque, this motor may fail to accelerate the high-inertia fan load within acceptable time. For a steel mill environment with voltage fluctuations, this is unacceptable.

95 mm² at 1,010 A starting current (BS 7671 / IEC):

ΔVstart = 1.732 × 1,010 × 150 × (0.236 × 0.25 + 0.110 × 0.968) / 1000

ΔVstart = 262,414 × 0.165 / 1000

ΔVstart = 43.3 V = 10.8% (of 400 V)

Motor terminal voltage = 400 − 43.3 = 356.7 V. Starting torque retention = (356.7 / 400)² = 79.5%.

Still below 80% terminal voltage. The motor will likely start but with marginal torque and extended acceleration time. For a high-inertia fan in a steel mill, this is a design risk.

4/0 AWG / 107 mm² at 1,010 A starting current (NEC):

ΔVstart = 1.732 × 1,010 × 150 × (0.203 × 0.25 + 0.110 × 0.968) / 1000

ΔVstart = 262,414 × 0.157 / 1000

ΔVstart = 41.2 V = 10.3% (of 400 V)

Motor terminal voltage = 400 − 41.2 = 358.8 V. Starting torque retention = (358.8 / 400)² = 80.5%.

The NEC selection just barely passes the 80% terminal voltage threshold — by only 0.5%.

Step 7: Upsize for Starting Voltage Drop

All four selections need review. The motor starting voltage drop at 150 m pushes every selection to the boundary. The next cable size up for each standard:

AS/NZS 3008: Upsize from 70 mm² to 120 mm²

From Table 35, 120 mm²: r = 0.188 mΩ/m, x = 0.100 mΩ/m

ΔVstart = 1.732 × 973 × 150 × (0.188 × 0.25 + 0.100 × 0.968) / 1000

ΔVstart = 252,801 × 0.144 / 1000

ΔVstart = 36.4 V = 8.8%

Motor terminal voltage = 415 − 36.4 = 378.6 V. Torque retention = (378.6/415)² = 83.2%. PASS.

BS 7671 / IEC: Upsize from 95 mm² to 120 mm²

From Table 4E2B, 120 mm²: r = 0.188 mΩ/m, x = 0.100 mΩ/m

ΔVstart = 1.732 × 1,010 × 150 × (0.188 × 0.25 + 0.100 × 0.968) / 1000

ΔVstart = 262,414 × 0.144 / 1000

ΔVstart = 37.8 V = 9.4%

Motor terminal voltage = 400 − 37.8 = 362.2 V. Torque retention = (362.2/400)² = 82.0%. PASS.

NEC: Upsize from 4/0 AWG to 250 kcmil (127 mm²)

From NEC Table 9, 250 kcmil: r = 0.171 mΩ/m, x = 0.105 mΩ/m

ΔVstart = 1.732 × 1,010 × 150 × (0.171 × 0.25 + 0.105 × 0.968) / 1000

ΔVstart = 262,414 × 0.145 / 1000

ΔVstart = 38.1 V = 9.5%

Motor terminal voltage = 400 − 38.1 = 361.9 V. Torque retention = (361.9/400)² = 81.9%. PASS.

Step 8: Protection Device Selection

Motor branch circuit protection varies significantly across standards:

ParameterAS/NZS 3000BS 7671IEC 60364NEC 430
Overload relay classClass 10AClass 10Class 10NEC 430.32 (115% FLC)
MCCB frame rating200 A200 A200 A200 A
Thermal trip setting1.05 × IFL1.05 × IFL1.05 × IFL1.15 × IFL (NEC 430.32)
Instantaneous trip max8–10 × In10 × In10 × InNEC 430.52: 250% for inverse-time
Short-circuit backupHRC fuse 250 ABS 88 fuse 250 AgG fuse 250 ADual-element fuse 250 A

NEC key difference (NEC 430.52): NEC explicitly limits motor branch circuit short-circuit and ground-fault protection to specific multiples of FLC — 250% for inverse-time breakers, 175% for dual-element fuses, 800% for instantaneous-trip breakers. This interacts with cable sizing because the protection device rating determines the minimum cable ampacity.

Result Summary

CheckAS/NZS 3008BS 7671IEC 60364NEC
Full-load current129.8 A134.6 A134.6 A134.6 A
Starting current973 A1,010 A1,010 A1,010 A
Combined derating0.6940.6350.6350.557
Cable (current capacity)70 mm²95 mm²95 mm²4/0 AWG (107 mm²)
Running VD%2.70% PASS2.27% PASS2.27% PASS2.02% PASS
Starting VD% (initial)11.3% FAIL10.8% FAIL10.8% FAIL10.3% MARGINAL
Final cable (after VD)120 mm²120 mm²120 mm²250 kcmil (127 mm²)
Starting VD% (final)8.8%9.4%9.4%9.5%
Starting torque retained83.2%82.0%82.0%81.9%
StatusPASSPASSPASSPASS

Multi-Standard Comparison

ParameterAS/NZS 3008BS 7671IEC 60364NEC
Nominal voltage415 V400 V400 V400 V
Reference ambient40°C30°C30°C30°C
Temp derating at 45°C0.95 (mild penalty)0.87 (significant penalty)0.870.87
Grouping derating (6 ccts)0.730.730.730.80 (tray more generous)
Continuous load factorNot explicitNot explicitNot explicit1.25 (NEC 430.22)
Cable for current capacity70 mm²95 mm²95 mm²107 mm²
Cable after starting VD120 mm²120 mm²120 mm²127 mm²
Governing factorStarting VDStarting VDStarting VDStarting VD
Copper weight (150 m)160 kg160 kg160 kg170 kg

Key Insight

The key finding in this example is that motor starting voltage drop — not steady-state current capacity — governs cable selection for all four standards when the route exceeds approximately 100 m for a 75 kW DOL motor. The cable sizes selected purely on current capacity (70 mm² to 107 mm²) all had to be upsized to 120–127 mm² once starting voltage drop was checked.

What makes this counterintuitive is the convergence: despite AS/NZS starting with a 70 mm² cable and NEC starting with 107 mm² (a 53% difference in copper), the final cable selections after voltage drop analysis are nearly identical at 120–127 mm². The standards diverge on current capacity but converge on starting voltage drop because the physics of impedance at 150 m are independent of the administrative differences between standards.

This has profound cost implications: an engineer who sizes a motor feeder cable only for steady-state current capacity under AS/NZS 3008 would specify 70 mm², using only 58% of the copper actually required. The motor would either fail to start, take dangerously long to accelerate, or draw excessive starting current from a reduced-voltage terminal — any of which can cause protection trips, voltage sags affecting other equipment, or motor winding damage from extended locked-rotor conditions.

Try the Cable Sizing Calculator

Put this methodology into practice. Calculate results with full standard clause references — free, no sign-up required.

Or embed this calculator on your site
Calculate Cable Sizing

Frequently Asked Questions

For a 75 kW DOL motor with 7.5x starting current, the crossover point where starting voltage drop forces a cable upsize beyond the current-capacity selection is approximately 80-100 m under most standards. Below this length, the cable selected for current capacity also satisfies starting voltage drop. Above this length, the starting voltage drop percentage exceeds the threshold for reliable motor starting (80% terminal voltage per IEEE 141), and the cable must be upsized regardless of its current rating. For soft-started or VFD-driven motors, the crossover point extends to 300-500 m because the starting current is reduced to 2-3x FLC.
Yes, significantly. Star-delta starting reduces starting current to approximately one-third of DOL starting current (I_start_SD = I_start_DOL / 3, approximately 2.5x FLC). For the 150 m run in this example, the starting voltage drop with star-delta would be approximately 3.0-3.5% instead of 9-11%, well within limits. The cable size would then be governed by steady-state current capacity: 70 mm² under AS/NZS, 95 mm² under BS/IEC, and 107 mm² under NEC. However, star-delta also reduces starting torque to one-third, which may be insufficient for the high-inertia fan load. The engineer must verify that the reduced starting torque exceeds the load torque at zero speed.
Three factors compound: (1) AS/NZS uses 415 V nominal versus 400 V, giving 3.7% lower full-load current, (2) AS/NZS uses 40°C reference ambient versus 30°C, so derating at 45°C is a mild 0.95 instead of 0.87, and (3) the AS/NZS cable current rating tables are based on different installation method assumptions. The first two factors reduce the required cable rating by approximately 20%, which is enough to drop from 95 mm² to 70 mm². This is not a safety deficiency — Australian conditions (higher ambient reference, higher nominal voltage) are genuinely different from European conditions, and the standard tables reflect this.

Related Resources