Challenge: Size a Cable for This 132kW Motor in a 45°C Ambient Tray Installation
Work through a real-world cable sizing challenge: 132kW, 415V, 3-phase motor on perforated tray at 45 degrees C ambient with 4 other circuits. Calculate design current, apply derating factors, select cable size per IEC 60364-5-52 and AS/NZS 3008.1.1, and verify voltage drop.
The Problem
| Parameter | Value |
|---|---|
| Motor rated power | 132 kW |
| Supply voltage | 415 V, 3-phase, 50 Hz |
| Motor power factor | 0.87 |
| Motor efficiency | 0.95 (IE3) |
| Cable run length | 45 m |
| Installation method | Perforated cable tray — IEC Reference Method E |
| Ambient temperature | 45°C |
| Other circuits on tray | 4 (total 5 circuits including this one) |
| Cable insulation | XLPE, copper conductors |
| Protection device | MCCB, to be selected |
| Voltage drop limit | 5% (20.75 V line-to-line) |
Take a moment. Calculate the design current. Identify the derating factors. Select the cable. Then read on.
Work Through It
Step 1: Calculate the design current (Ib).
The motor draws power from the supply. The supply current includes losses in the motor (efficiency) and the reactive component (power factor):
Ib = P / (√3 × V × PF × η)
Ib = 132,000 / (√3 × 415 × 0.87 × 0.95)
Ib = 132,000 / (1.732 × 415 × 0.87 × 0.95)
Ib = 132,000 / 594.0
Ib = 222.2 A
Step 2: Select the protection device rating (In).
The MCCB must be rated at or above Ib. Standard MCCB ratings: 200, 225, 250, 315, 400 A. For a motor circuit, also consider starting current — but for cable sizing, we need In ≥ Ib:
In = 250 A (next standard rating above 222.2 A)
Step 3: Determine the required tabulated current (It).
The cable must carry In after derating factors are applied:
It ≥ In / (Ca × Cg)
Where Ca is the ambient temperature correction factor and Cg is the grouping correction factor.
Ambient temperature correction (Ca):
For XLPE insulation (90°C maximum operating temperature) at 45°C ambient, from IEC 60364-5-52, Table B.52.14:
Ca = 0.87
Grouping correction (Cg):
For 5 circuits on a perforated tray (single layer, touching), from IEC 60364-5-52, Table B.52.17:
Cg = 0.73
Required tabulated current:
It ≥ 250 / (0.87 × 0.73)
It ≥ 250 / 0.635
It ≥ 393.7 A
The Solution
IEC 60364-5-52 selection:
From IEC 60364-5-52, Table B.52.10 (Reference Method E, XLPE, copper, 3-phase), find the cable with tabulated current ≥ 393.7 A:
| Cable Size (mm²) | Tabulated Current (A) | Adequate? |
|---|---|---|
| 120 | 346 | No — 346 < 393.7 |
| 150 | 391 | No — 391 < 393.7 |
| 185 | 448 | Yes — 448 > 393.7 |
Selected cable: 185 mm² 4-core XLPE/copper
Note the 150 mm² cable at 391 A is tantalisingly close to the required 393.7 A. This is where shortcuts kill you. A 2.7 A shortfall means the cable is undersized. There is no rounding down in cable sizing.
AS/NZS 3008.1.1:2017 comparison:
Under AS/NZS 3008.1.1:2017, the reference ambient is 40°C. The ambient derating from 40°C to 45°C is less severe (Ca = 0.90 from Table 6), but the base tabulated currents in Table 13 for the same installation method may differ slightly. The grouping factors from Table 22 for 5 circuits on a perforated tray give Cg = 0.73 (same as IEC for this configuration). Working through the AS/NZS calculation typically yields the same 185 mm² result for this scenario, though the margin is more comfortable because the ambient derating is less severe.
Voltage Drop Check
Cable sized for current capacity — now verify voltage drop. For 185 mm² copper cable at 45 m:
From IEC 60364-5-52 tables or manufacturer data, the mV/A/m value for 185 mm² 4-core XLPE at 0.87 PF is approximately 0.23 mV/A/m (combining resistive and reactive components).
Vd = (mV/A/m × Ib × L) / 1000
Vd = (0.23 × 222.2 × 45) / 1000
Vd = 2.30 V
As a percentage of supply voltage:
Vd% = (2.30 / 415) × 100 = 0.55%
This is well within the 5% limit (20.75 V). Voltage drop is not the governing factor for this installation — the cable size is determined by current capacity after derating.
If the run were longer — say 200 m (common in mining and industrial plants) — voltage drop would become the controlling factor and might push the cable to 240 mm² or beyond, regardless of current capacity.
Key Learning
What made this challenge tricky:
- The combined derating factor is severe. Ca × Cg = 0.635. The cable must carry 57% more current than the protection device rating to account for the hot, crowded installation environment. Engineers who forget either factor — or who apply them to Ib instead of In — will undersize the cable.
- The 150 mm² trap. At 391 A versus 393.7 A required, the 150 mm² cable looks adequate at first glance. It is not. A cable that is 99.3% of the required rating is still undersized. In a real installation, this 2.7 A margin could be consumed by any deviation from assumed conditions.
- Motor efficiency matters. Omitting the 0.95 efficiency factor would give Ib = 211 A instead of 222 A. That 11 A difference would not change the cable size in this case, but in a borderline scenario it is the difference between a cable that passes and one that does not.
- Power factor in the design current. PF = 0.87 means the motor draws more current per kilowatt of mechanical output than a unity PF load. Forgetting PF in the Ib calculation is the most common motor cable sizing error — it undersizes the cable by approximately 15%.
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