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Challenge: Is This Transformer Earthing System Compliant with IEC 60364-4-41?

Verify earth fault loop impedance compliance for a 1000kVA transformer with a 250m LV feeder. Calculate phase and PE conductor resistance at operating temperature, determine total Zs, check disconnection time per IEC 60364-4-41 Table 41.1, and assess touch voltage.

IEC 603645 min readUpdated March 12, 2026
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The Problem

Challenge: A 250 m LV feeder runs from a 1000 kVA transformer to a remote sub-distribution board. Is the earthing arrangement compliant with IEC 60364-4-41 for automatic disconnection? Work through the earth fault loop impedance before reading the verdict.
ParameterValue
Transformer1000 kVA, 11kV/415V, Dyn11
Transformer impedance6% (ZT)
System typeTN-S
LV feeder cable185 mm² 4-core XLPE aluminium + 95 mm² copper PE
Feeder length250 m
Protection at transformer LV100 A MCCB (thermal-magnetic)
System voltage415 V line-to-line, 240 V line-to-neutral
Conductor operating temperature80°C (XLPE under load)

This is a distribution circuit feeding a sub-board. Per IEC 60364-4-41, Table 41.1, the maximum disconnection time for a distribution circuit in a TN system is 5 seconds.

Calculate Earth Fault Loop Impedance

Step 1: Transformer source impedance (Zsource).

The transformer impedance referred to the LV side:

ZT = (V2 / S) × z%

ZT = (4152 / 1,000,000) × 0.06

ZT = 0.1722 × 0.06 = 0.01033 Ω

For earth fault loop calculation, the relevant impedance is the transformer winding impedance in the fault loop. For a Dyn11 transformer with TN-S earthing, Zsource ≈ ZT = 0.010 Ω (predominantly reactive at this size).

Step 2: Phase conductor resistance (R1) — 185 mm² aluminium at 80°C.

Aluminium conductor resistance at 20°C: ρ20 = 0.0283 Ω·mm²/m.

Temperature correction to 80°C:

R80 = R20 × [1 + α × (80 − 20)]

Where α = 0.00403 /°C for aluminium:

R1/m = (0.0283 / 185) × [1 + 0.00403 × 60]

R1/m = 0.000153 × 1.2418 = 0.000190 Ω/m

For 250 m:

R1 = 0.000190 × 250 = 0.0475 Ω

Step 3: Protective conductor resistance (R2) — 95 mm² copper at 80°C.

Copper conductor resistance at 20°C: ρ20 = 0.01724 Ω·mm²/m.

Temperature correction to 80°C (α = 0.00393 /°C for copper):

R2/m = (0.01724 / 95) × [1 + 0.00393 × 60]

R2/m = 0.0001815 × 1.2358 = 0.000224 Ω/m

For 250 m:

R2 = 0.000224 × 250 = 0.0560 Ω

Step 4: Total earth fault loop impedance (Zs).

Zs = Zsource + R1 + R2

Zs = 0.010 + 0.0475 + 0.0560

Zs = 0.1135 Ω

Check Disconnection Time

Step 5: Calculate prospective earth fault current.

If = Uo / Zs = 240 / 0.1135 = 2,115 A

Step 6: Verify disconnection within 5 seconds.

Per IEC 60364-4-41, Table 41.1, for a TN system distribution circuit, the maximum disconnection time is 5 seconds. The 100 A thermal-magnetic MCCB must trip within 5 seconds at 2,115 A.

For a 100 A MCCB conforming to IEC 60947-2:

  • The magnetic (instantaneous) trip threshold is typically 5–10 × In = 500–1,000 A (adjustable on most industrial MCCBs)
  • Our fault current of 2,115 A significantly exceeds the maximum instantaneous trip threshold of 1,000 A
  • The MCCB will trip instantaneously — within approximately 20–50 ms

Result: PASS. The disconnection time is well within the 5-second requirement. The 2,115 A fault current is more than twice the maximum instantaneous trip setting, so the MCCB trips in its magnetic region with substantial margin.

Touch Voltage Check

While the disconnection time is satisfactory, we should also check the prospective touch voltage during the fault — this is the voltage that appears on exposed metalwork at the sub-board during the brief period before the MCCB trips.

Touch voltage = If × R2(downstream)

Where R2(downstream) is the resistance of the PE conductor from the fault point back to the sub-board earth bar. For a fault at the sub-board:

Vtouch = If × R2 = 2,115 × 0.0560 = 118.4 V

This is a significant touch voltage. At 118 V, the IEC 60364-4-41 requirements for automatic disconnection become critical — the faster the disconnection, the lower the shock risk. Our MCCB trips instantaneously (20–50 ms), which is within the safe disconnection time curves for this voltage level.

However, consider what happens if the MCCB instantaneous trip is adjusted to a higher setting (as sometimes done to avoid nuisance tripping on motor starting at the sub-board). If the instantaneous setting were raised to 15 × In = 1,500 A, and the fault current were lower than calculated (perhaps due to higher conductor temperature or additional connection resistance), the MCCB might operate in its thermal-magnetic time-delay region. At 2,115 A on the thermal curve, the trip time could be 1–3 seconds — still within the 5-second limit, but exposing anyone touching the sub-board metalwork to 118 V for up to 3 seconds.

The Verdict and Remediation

Compliant? Yes. The earth fault loop impedance of 0.1135 Ω produces a fault current of 2,115 A, which trips the 100 A MCCB instantaneously — well within the 5-second disconnection requirement for a distribution circuit under IEC 60364-4-41.

But is it robust? Consider the following sensitivities:

ScenarioZs (Ω)If (A)Trips Instantaneously?
As designed (80°C)0.1142,115Yes
Higher temperature (90°C)0.1202,000Yes
Additional 50m extension0.1451,655Yes (if Imag ≤ 1,000A)
Aluminium PE instead of copper0.1401,714Yes (if Imag ≤ 1,000A)

The design has margin, but that margin erodes with cable extensions, higher operating temperatures, or PE conductor substitution. If this sub-board will feed final circuits (not just other distribution circuits), those final circuits have a 0.4-second disconnection requirement — and the Zs at the end of those final circuits includes the 0.1135 Ω contribution from this feeder.

If remediation were needed, the most effective options are:

  1. Increase PE conductor size. A 120 mm² copper PE instead of 95 mm² reduces R2 by 21%, providing significant margin for downstream circuits.
  2. Add RCD protection at the sub-board. A time-delayed RCD (Type S, 100 ms) at the sub-board provides backup disconnection for earth faults that produce lower fault currents than the MCCB can detect quickly.
  3. Earth fault relay. For industrial installations, a dedicated earth fault relay with adjustable pickup and time settings provides more precise control over earth fault disconnection than relying on the MCCB’s overcurrent characteristics.

Standards referenced: IEC 60364-4-41:2005+A1:2017 (Table 41.1), IEC 60364-5-54 (protective conductors), IEC 60947-2 (MCCBs).

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Frequently Asked Questions

This is common practice for long LV feeders. Aluminium phase conductors reduce cost and weight for the large cross-section needed for current capacity. The PE conductor is copper because it provides lower resistance for a given cross-section, improving earth fault loop impedance. The PE conductor also needs to withstand the thermal energy of the fault current without damage — copper has better thermal withstand than aluminium for the same cross-section. This mixed-material approach optimises both cost and fault performance.
Distribution circuits feed sub-boards, not final loads that people directly touch. The 0.4-second requirement protects against electric shock from hand-held or portable equipment connected to final circuits. Distribution circuits have a longer permitted disconnection time (5 seconds per IEC 60364-4-41 Table 41.1) because the risk of direct contact with distribution circuit metalwork is lower — sub-boards are typically enclosed and accessed only by trained personnel. The final circuits downstream still require 0.4-second disconnection.
Use operating temperature (typically 70-90 degrees C depending on insulation type) for the worst-case earth fault loop impedance calculation. This gives the highest resistance and lowest fault current — the conservative result. Some standards (including BS 7671) publish conductor resistances at operating temperature specifically for this purpose. Using 20 degrees C resistance would overestimate the fault current and underestimate the disconnection time, giving an unconservative result.

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